GED Mathematical Reasoning Preparation Course: Graphs, lines and functions
Questionário temático sem limite de tempo: 16 perguntas sobre Graphs, lines and functions, com uma explicação depois de cada resposta. As perguntas e respostas são baralhadas de cada vez.
Questionário temático 6: Graphs, lines and functions
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Pergunta 1 de 16
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Resposta: C. Quadrant II
x is negative (left) and y is positive (up), so the point is in Quadrant II, the upper left.
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Pergunta 2 de 16
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Resposta: B. 2
Slope = (y₂ − y₁) ÷ (x₂ − x₁) = (11 − 3) ÷ (6 − 2) = 8 ÷ 4 = 2.
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Pergunta 3 de 16
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Resposta: A. −3
In y = mx + b, m is the slope. Here m = −3.
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Pergunta 4 de 16
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Resposta: D. 6
Solve for y: y = −2x + 6. The y-intercept is b = 6, the point (0, 6). The x-intercept is 3.
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Pergunta 5 de 16
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Resposta: D. The worker earns $18 per hour
Slope = change in pay ÷ change in hours = $18 ÷ 1 hour. The slope is the unit rate: $18 per hour.
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Pergunta 6 de 16
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Resposta: C. y = 2x + 3
Slope = (9 − 5) ÷ (3 − 1) = 2. Use (1, 5): 5 = 2(1) + b, so b = 3. The line is y = 2x + 3.
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Pergunta 7 de 16
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Resposta: A. y = −4x + 7
Point-slope form: y − (−1) = −4(x − 2), so y + 1 = −4x + 8 and y = −4x + 7.
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Pergunta 8 de 16
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Resposta: C. y = 5x + 8
Parallel lines have the same slope. Only y = 5x + 8 has a slope of 5.
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Pergunta 9 de 16
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Resposta: B. −3/2
Perpendicular slopes are negative reciprocals. Flip 2/3 to 3/2 and change the sign: −3/2.
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Pergunta 10 de 16
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Resposta: D. (1, 3), (2, 3), (3, 5)
In a function, each input (x) has only one output (y). The other sets repeat an x with a different y. Two inputs may share an output.
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Pergunta 11 de 16
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Resposta: D. 10
Replace x with 3: 2(9) − 3(3) + 1 = 18 − 9 + 1 = 10. Square 3 first, then multiply by 2.
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Pergunta 12 de 16
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Resposta: D. Car A, by 2 mph
Car A's rate is 210 ÷ 3.5 = 60 mph. Car B's rate is the slope, 58 mph. 60 − 58 = 2 mph.
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Pergunta 13 de 16
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Resposta: A. f has the greater rate of change
f has slope 3 and y-intercept 2. In the table, g goes up 2 for each 1 in x, so its slope is 2, and its y-intercept is 5.
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Pergunta 14 de 16
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Resposta: C. At x = 2 and x = −2
The graph crosses the x-axis where y = 0: x² − 4 = 0, so x² = 4 and x = 2 or −2. (0, −4) is the y-intercept and lowest point.
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Pergunta 15 de 16
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Resposta: B. 2 seconds
The highest point of y = ax² + bx + c is at x = −b ÷ (2a) = −64 ÷ (−32) = 2 seconds. Its height then is 64 feet.
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Pergunta 16 de 16
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Resposta: D. v = −3,000x + 24,000
The value starts at $24,000 (the y-intercept) and drops $3,000 a year (a slope of −3,000).
Teclado: 1–4 para responder, Enter para a pergunta seguinte.
O exame real: 145 on each GED subject